Factors of 325 in pair are (1, 325) , (5, 65) and (13, 25)

- Find all the numbers that would divide 325 without leaving any remainder. Starting with the number 1 upto 162 (half of 325). The number 1 and the number itself are always factors of the given number.
- Pair the factors so that their product is 325, and read off the answer!

Factor Pair | Pair Factorization |
---|---|

1 and 325 | 1 x 325 = 325 |

5 and 65 | 5 x 65 = 325 |

13 and 25 | 13 x 25 = 325 |

Since the product of two negative numbers gives a positive number, the product of the negative values of both the numbers in a pair factor will also give 325. They are called negative pair factors.

Hence, the negative pairs of 325 would be ( -1 , -325 ) .

In mathematics, factor pair are often given as pair of numbers which when multiplied together give the original number. Every natural number is a product of atleast one factor pair. Eg- Factors of 325 are 1 , 5 , 13 , 25 , 65 , 325. So, factors of 325 in pair are (1,325), (5,65), (13,25).

In mathematics, a factor is that number which divides into another number exactly, without leaving a remainder. A factor of a number can be positive or negative.

- Every factor of a number is an exact divisor of that number, example 1, 5, 13, 25, 65, 325 are exact divisors of 325.
- Every number other than 1 has at least two factors, namely the number itself and 1.
- Each number is a factor of itself. Eg. 325 is a factor of itself.
- 1 is a factor of every number. Eg. 1 is a factor of 325.

**Step 1.**Find all the numbers that would divide 325 without leaving any remainder. Starting with the number 1 upto 162 (half of 325). The number 1 and the number itself are always factors of the given number.325 ÷ 1 : Remainder = 0325 ÷ 5 : Remainder = 0325 ÷ 13 : Remainder = 0325 ÷ 25 : Remainder = 0325 ÷ 65 : Remainder = 0325 ÷ 325 : Remainder = 0

Hence, Factors of
*325* are **1, 5, 13, 25, 65, and 325**

**Is there any even prime factor of 325?**No there is no even prime factor, i.e. 2, of 325.

**What is the mean of all prime factors of 325?**Factors of 325 are 1 , 5 , 13 , 25 , 65 , 325. Prime factors of 325 are 5 , 5 , 13. Therefore mean of prime factors of 325 is (5 + 5 + 13) / 3 = 7.67.

**What is the mean of factors of 325?**Factors of 325 are 1 , 5 , 13 , 25 , 65 , 325. therefore mean of factors of 325 is (1 + 5 + 13 + 25 + 65 + 325) / 6 = 72.33.

**What do you mean by proper divisors?**A number x is said to be the proper divisor of y if it divides y completely, given that x is smaller than y.

**What do you mean by improper divisors?**An improper divisor of a number is the number itself apart from this any divisor of a given number is a proper divisor.

Factors of 325 are 1, 5, 13, 25, 65, 325. So, factors of 325 in pair are (1,325), (5,65), (13,25).

Factors of 325 are 1, 5, 13, 25, 65, 325. So, factors of 325 in pair are (1,325), (5,65), (13,25).

Factors of 325 are 1, 5, 13, 25, 65, 325. Hence, the factors of 325 in pair are (1,325), (5,65), (13,25).

Factors of 325 are 1, 5, 13, 25, 65, 325.

Factors of 325 in pair are (1,325), (5,65), (13,25).

Prime factorization of 325 is 5 x 5 x 13. Factors of 325 in pair can be written as (1,325), (5,65), (13,25).

Smallest prime factor of 325 is 5.

Largest prime factor of 325 is 13.

Negative factors of 325 are -1, -5, -13, -25, -65, -325.