Factors of 520 in pair

Steps to find factors of 520 in pair

Find all the numbers that would divide 520 without leaving any remainder. Starting with the number 1 upto 260 (half of 520). The number 1 and the number itself are always factors of the given number.
Pair the factors so that their product is 520, and read off the answer!

Example: Find factors of 520 in pair

Factor Pair	Pair Factorization
1 and 520	1 x 520 = 520
2 and 260	2 x 260 = 520
4 and 130	4 x 130 = 520
5 and 104	5 x 104 = 520
8 and 65	8 x 65 = 520
10 and 52	10 x 52 = 520
13 and 40	13 x 40 = 520
20 and 26	20 x 26 = 520

Since the product of two negative numbers gives a positive number, the product of the negative values of both the numbers in a pair factor will also give 520. They are called negative pair factors.

Hence, the negative pairs of 520 would be ( -1 , -520 ) .

Definition of factor pairs?

In mathematics, factor pair are often given as pair of numbers which when multiplied together give the original number. Every natural number is a product of atleast one factor pair. Eg- Factors of 520 are 1 , 2 , 4 , 5 , 8 , 10 , 13 , 20 , 26 , 40 , 52 , 65 , 104 , 130 , 260 , 520. So, factors of 520 in pair are (1,520), (2,260), (4,130), (5,104), (8,65), (10,52), (13,40), (20,26).

What are factors?

In mathematics, a factor is that number which divides into another number exactly, without leaving a remainder. A factor of a number can be positive or negative.

Properties of Factors

Each number is a factor of itself. Eg. 520 is a factor of itself.
1 is a factor of every number. Eg. 1 is a factor of 520.
Every number is a factor of zero (0), since 520 x 0 = 0.
Every number other than 1 has at least two factors, namely the number itself and 1.
Every factor of a number is an exact divisor of that number, example 1, 2, 4, 5, 8, 10, 13, 20, 26, 40, 52, 65, 104, 130, 260, 520 are exact divisors of 520.
Factors of 520 are 1, 2, 4, 5, 8, 10, 13, 20, 26, 40, 52, 65, 104, 130, 260, 520. Each factor divides 520 without leaving a remainder.
Every factor of a number is less than or equal to the number, eg. 1, 2, 4, 5, 8, 10, 13, 20, 26, 40, 52, 65, 104, 130, 260, 520 are all less than or equal to 520.

Steps to find Factors of 520

Step 1. Find all the numbers that would divide 520 without leaving any remainder. Starting with the number 1 upto 260 (half of 520). The number 1 and the number itself are always factors of the given number.

520 ÷ 1 : Remainder = 0

520 ÷ 2 : Remainder = 0

520 ÷ 4 : Remainder = 0

520 ÷ 5 : Remainder = 0

520 ÷ 8 : Remainder = 0

520 ÷ 10 : Remainder = 0

520 ÷ 13 : Remainder = 0

520 ÷ 20 : Remainder = 0

520 ÷ 26 : Remainder = 0

520 ÷ 40 : Remainder = 0

520 ÷ 52 : Remainder = 0

520 ÷ 65 : Remainder = 0

520 ÷ 104 : Remainder = 0

520 ÷ 130 : Remainder = 0

520 ÷ 260 : Remainder = 0

520 ÷ 520 : Remainder = 0

Hence, Factors of 520 are 1, 2, 4, 5, 8, 10, 13, 20, 26, 40, 52, 65, 104, 130, 260, and 520

Frequently Asked Questions

Is 520 a composite number?
Yes 520 is a composite number.
Is 520 a prime number?
No 520 is not a prime number.
Write five multiples of 520.
Five multiples of 520 are 1040, 1560, 2080, 2600, 3120.
Write all odd factors of 520?
The factors of 520 are 1, 2, 4, 5, 8, 10, 13, 20, 26, 40, 52, 65, 104, 130, 260, 520.
Odd factors of 520 are 1 , 5 , 13 , 65.
What is the mean of all prime factors of 520?
Factors of 520 are 1 , 2 , 4 , 5 , 8 , 10 , 13 , 20 , 26 , 40 , 52 , 65 , 104 , 130 , 260 , 520. Prime factors of 520 are 2 , 2 , 2 , 5 , 13. Therefore mean of prime factors of 520 is (2 + 2 + 2 + 5 + 13) / 5 = 4.80.

Examples of Factors

Ariel has been asked to write all factor pairs of 520 but she is finding it difficult. Can you help her find out?

Factors of 520 are 1, 2, 4, 5, 8, 10, 13, 20, 26, 40, 52, 65, 104, 130, 260, 520. So, factors of 520 in pair are (1,520), (2,260), (4,130), (5,104), (8,65), (10,52), (13,40), (20,26).

Sammy wants to write all the negative factors of 520 in pair, but don't know how to start. Help Sammy in writing all the factor pairs.

Negative factors of 520 are -1, -2, -4, -5, -8, -10, -13, -20, -26, -40, -52, -65, -104, -130, -260, -520. Hence, factors of 520 in pair are (-1,-520), (-2,-260), (-4,-130), (-5,-104), (-8,-65), (-10,-52), (-13,-40), (-20,-26).

Help Deep in writing the positive factors of 520 in pair and negative factor of 520 in pair.

Factors of 520 are 1, 2, 4, 5, 8, 10, 13, 20, 26, 40, 52, 65, 104, 130, 260, 520. Positive factors of 520 in pair are (1,520), (2,260), (4,130), (5,104), (8,65), (10,52), (13,40), (20,26). Negative factors of 520 in pair are (-1,-520), (-2,-260), (-4,-130), (-5,-104), (-8,-65), (-10,-52), (-13,-40), (-20,-26).

Find the product of all factors of 520.

Factors of 520 are 1, 2, 4, 5, 8, 10, 13, 20, 26, 40, 52, 65, 104, 130, 260, 520. So the product of all factors of 520 would be 1 x 2 x 4 x 5 x 8 x 10 x 13 x 20 x 26 x 40 x 52 x 65 x 104 x 130 x 260 x 520 = 5.3459728531456e+21.

Find the product of all prime factors of 520.

Factors of 520 are 1, 2, 4, 5, 8, 10, 13, 20, 26, 40, 52, 65, 104, 130, 260, 520. Prime factors are 2, 2, 2, 5, 13. So, the product of all prime factors of 520 would be 2 x 2 x 2 x 5 x 13 = 520.

Can you help Sammy list the factors of 520 and also find the factor pairs?

Factors of 520 are 1, 2, 4, 5, 8, 10, 13, 20, 26, 40, 52, 65, 104, 130, 260, 520.
Factors of 520 in pair are (1,520), (2,260), (4,130), (5,104), (8,65), (10,52), (13,40), (20,26).

Sammy has 520 blocks and he wants to arrange them in all possible ways to form a rectangle but he doesn't know the technique for doing that, help Sammy in arrangements.

To arrange 520 blocks in all possible ways to form a rectangle, we need to calculate factors of 520 in pair. Therefore, factors of 520 in pair are (1,520), (2,260), (4,130), (5,104), (8,65), (10,52), (13,40), (20,26)

How to find factors of a number in pair