1. Steps to find factors of 537 using Division Method

Example: Find factors of 537

  • Divide 537 by 1: 537 ÷ 1 : Remainder = 0
  • Divide 537 by 3: 537 ÷ 3 : Remainder = 0
  • Divide 537 by 179: 537 ÷ 179 : Remainder = 0
  • Divide 537 by 537: 537 ÷ 537 : Remainder = 0

Hence, Factors of 537 are 1, 3, 179, and 537

2. Steps to find factors of 537 using Prime Factorization

A prime number is a number that has exactly two factors, 1 and the number itself. Prime factorization of a number means breaking down of the number into the form of products of its prime factors.

There are two different methods that can be used for the prime factorization.

Method 1: Division Method

To find the primefactors of 537 using the division method, follow these steps:

  • Step 1. Start dividing 537 by the smallest prime number, i.e., 2, 3, 5, and so on. Find the smallest prime factor of the number.
  • Step 2. After finding the smallest prime factor of the number 537, which is 3. Divide 537 by 3 to obtain the quotient (179).
    537 ÷ 3 = 179
  • Step 3. Repeat step 1 with the obtained quotient (179).
    179 ÷ 179 = 1

So, the prime factorization of 537 is, 537 = 3 x 179.

Method 2: Factor Tree Method

We can follow the same procedure using the factor tree of 537 as shown below:

So, the prime factorization of 537 is, 537 = 3 x 179.

3. Find factors of 537 in Pairs

Pair factors of a number are any two numbers which, which on multiplying together, give that number as a result. The pair factors of 537 would be the two numbers which, when multiplied, give 537 as the result.

The following table represents the calculation of factors of 537 in pairs:

Factor Pair Pair Factorization
1 and 537 1 x 537 = 537
3 and 179 3 x 179 = 537

Since the product of two negative numbers gives a positive number, the product of the negative values of both the numbers in a pair factor will also give 537. They are called negative pair factors.

Hence, the negative pairs of 537 would be ( -1 , -537 ) , ( -3 , -179 ) .

How do you explain factors?

In mathematics, a factor is a number or also it can be an algebraic expression that divides another number or any expression completely and that too without leaving any remainder. A factor of a number can be positive or negative.

Properties of factors

  • Every factor of a number is an exact divisor of that number, example 1, 3, 179, 537 are exact divisors of 537.
  • Every number other than 1 has at least two factors, namely the number itself and 1.
  • Each number is a factor of itself. Eg. 537 is a factor of itself.
  • 1 is a factor of every number. Eg. 1 is a factor of 537.

Frequently Asked Questions

  • How do you find factors of a negative number? ( eg. -537 )?

    Factors of -537 are -1, -3, -179, -537.

  • What is the sum of all factors of 537?

    The sum of all factors of 537 is 720.

  • What is prime factorization of 537?

    Prime factorization of 537 is 3 x 179.

  • What are the pair factors of 537?

    Pair factors of 537 are (1,537), (3,179).

  • What are six multiples of 537?

    First five multiples of 537 are 1074, 1611, 2148, 2685, 3222, 3759.

  • Is 537 a whole number?

    Yes 537 is a whole number.

  • Which is the smallest prime factor of 537?

    Smallest prime factor of 537 is 3.

  • What are five multiples of 537?

    First five multiples of 537 are 1074, 1611, 2148, 2685, 3222.

  • Write all factors of 537?

    Factors of 537 are 1, 3, 179, 537.

Examples of Factors

Joey wants to write all the prime factors of 537 in exponential form, but he doesn't know how to do so can you assist him in this task?

Prime factors of 537 are 3, 179.
So in exponential form it can be written as 3 x 179.

How many factors are there for 537?

Factors of 537 are 1, 3, 179, 537.
So there are in total 4 factors.

Kevin has been asked to write 3 factor(s) of 537. Can you predict the answer?

3 factor(s) of 537 are 1, 3, 179.

Sammy is puzzled while calculating the prime factors of 537. Can you help him find them?

Factors of 537 are 1, 3, 179, 537.
Prime factors of 537 are 3, 179

What is prime factorization of 537?

Prime factorization of 537 is 3 x 179 = 3 x 179.

Ariel has been assigned the task to find the product of all the prime factors of 537. Can you help her?

Prime factors of 537 are 3, 179.
Hence, the product of prime factors of 537.

Can you help Rubel to find out the product of the even factors of 537?

Factors of 537 are 1, 3, 179, 537.
Even factors of 537 are 0.
Hence, product of even factors of 537 is; 0 = 0.