Factors of 3500 that add upto 135

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Factors of 3500 that add upto 135 are 1, 2, 7, and 125

How to find factors of 3500 that add upto 135

Steps to find factors of 3500 that add upto 135

Find all factors.
Then we find the sum of combinations of factors.
Note down the combination of factors with sum as 135, and read off the answer!

Example: Find factors of 3500 that add upto 135

Sum of 1, 2, 7, and 125 : 1 + 2 + 7 + 125 = 135

Hence, factors of 3500 that add upto 135 are 1, 2, 7, and 125.

Steps to find Factors of 3500

Step 1. Find all the numbers that would divide 3500 without leaving any remainder. Starting with the number 1 upto 1750 (half of 3500). The number 1 and the number itself are always factors of the given number.

3500 ÷ 1 : Remainder = 0

3500 ÷ 2 : Remainder = 0

3500 ÷ 4 : Remainder = 0

3500 ÷ 5 : Remainder = 0

3500 ÷ 7 : Remainder = 0

3500 ÷ 10 : Remainder = 0

3500 ÷ 14 : Remainder = 0

3500 ÷ 20 : Remainder = 0

3500 ÷ 25 : Remainder = 0

3500 ÷ 28 : Remainder = 0

3500 ÷ 35 : Remainder = 0

3500 ÷ 50 : Remainder = 0

3500 ÷ 70 : Remainder = 0

3500 ÷ 100 : Remainder = 0

3500 ÷ 125 : Remainder = 0

3500 ÷ 140 : Remainder = 0

3500 ÷ 175 : Remainder = 0

3500 ÷ 250 : Remainder = 0

3500 ÷ 350 : Remainder = 0

3500 ÷ 500 : Remainder = 0

3500 ÷ 700 : Remainder = 0

3500 ÷ 875 : Remainder = 0

3500 ÷ 1750 : Remainder = 0

3500 ÷ 3500 : Remainder = 0

Hence, Factors of 3500 are 1, 2, 4, 5, 7, 10, 14, 20, 25, 28, 35, 50, 70, 100, 125, 140, 175, 250, 350, 500, 700, 875, 1750, and 3500

What are factors?

In mathematics, the term factor is used for that number which divides the other number to leave 0 as a remainder. A factor of a number can be positive or negative.

Properties of Factors

Factors and multiples are two different terms. Factors are those number which when multiplied together give the number itself, on the other hand multiples are what we get after multiplying the same number with and other number.
Prime factors are those factors which are further divisible by only two numbers i.e. 1 ans the factor itself.
Every number is a factor of zero (0), since 3500 x 0 = 0.
Every number other than 1 has at least two factors, namely the number itself and 1.
Every factor of a number is an exact divisor of that number, example 1, 2, 4, 5, 7, 10, 14, 20, 25, 28, 35, 50, 70, 100, 125, 140, 175, 250, 350, 500, 700, 875, 1750, 3500 are exact divisors of 3500.

Examples

How many factors are there for 3500?

Factors of 3500 are 1, 2, 4, 5, 7, 10, 14, 20, 25, 28, 35, 50, 70, 100, 125, 140, 175, 250, 350, 500, 700, 875, 1750, 3500.
So there are in total 24 factors.

Raju wishes to write all the prime factors of 3500. Can you assist him in doing the same?

Factors of 3500 are 1, 2, 4, 5, 7, 10, 14, 20, 25, 28, 35, 50, 70, 100, 125, 140, 175, 250, 350, 500, 700, 875, 1750, 3500.
Prime factors of 3500 are 2, 2, 5, 5, 5, 7.

Can you assist Aubrey in finding factors of 3500 that add upto 135?

Factors of 3500 are 1, 2, 4, 5, 7, 10, 14, 20, 25, 28, 35, 50, 70, 100, 125, 140, 175, 250, 350, 500, 700, 875, 1750, 3500.
Factors of 3500 that add upto 135 are 1, 2, 7, 125, as 1 + 2 + 7 + 125 = 135.

Can you help Diji in finding sum of all even factors of 3500?

Factors of 3500 are 1, 2, 4, 5, 7, 10, 14, 20, 25, 28, 35, 50, 70, 100, 125, 140, 175, 250, 350, 500, 700, 875, 1750, 3500.
Even factors of 3500 are 2, 4, 10, 14, 20, 28, 50, 70, 100, 140, 250, 350, 500, 700, 1750, 3500.
Hence, sum of even factors of 3500 is; 2 + 4 + 10 + 14 + 20 + 28 + 50 + 70 + 100 + 140 + 250 + 350 + 500 + 700 + 1750 + 3500 = 7488.

Rustom is wondering to find the factors of 3500 that add upto 135, but is stuck. Assist Rustom in writing the same.

What are the negative pair factors of 3500?

Negative factors of 3500 are -1, -2, -4, -5, -7, -10, -14, -20, -25, -28, -35, -50, -70, -100, -125, -140, -175, -250, -350, -500, -700, -875, -1750, -3500. Hence, factors of 3500 in pair are (-1,-3500), (-2,-1750), (-4,-875), (-5,-700), (-7,-500), (-10,-350), (-14,-250), (-20,-175), (-25,-140), (-28,-125), (-35,-100), (-50,-70).

Help Rudolph in finding the product of factors of 3500?

Factors of 3500 are 1, 2, 4, 5, 7, 10, 14, 20, 25, 28, 35, 50, 70, 100, 125, 140, 175, 250, 350, 500, 700, 875, 1750, 3500.
Therefore, product of factors of 3500 is; 1 x 2 x 4 x 5 x 7 x 10 x 14 x 20 x 25 x 28 x 35 x 50 x 70 x 100 x 125 x 140 x 175 x 250 x 350 x 500 x 700 x 875 x 1750 x 3500 = 3.379220508056641e+42.