Definition of GCF
Greatest common factor commonly known as GCF of the two numbers is the highest possible number which completely divides given numbers, i.e. without leaving any remainder. It is represented as GCF (1050, 294).
Properties of GCF
- Given two numbers 1050 and 294, such that GCF is 42 where 42 will always be less than 1050 and 294.
- GCF of two numbers is always equal to 1 in case given numbers are consecutive.
- The product of GCF and LCM of two given numbers is equal to the product of two numbers.
- The GCF of two given numbers is either 1 or the number itself if one of them is a prime number.
What are factors?
In mathematics, a factor is that number which divides into another number exactly, without leaving a remainder. A factor of a number can be positive or negative.
Properties of Factors
- Each number is a factor of itself. Eg. 1050 and 294 are factors of themselves respectively.
- Every number other than 1 has at least two factors, namely the number itself and 1.
- Every factor of a number is an exact divisor of that number, example 1, 2, 3, 5, 6, 7, 10, 14, 15, 21, 25, 30, 35, 42, 50, 70, 75, 105, 150, 175, 210, 350, 525, 1050 are exact divisors of 1050 and 1, 2, 3, 6, 7, 14, 21, 42, 49, 98, 147, 294 are exact divisors of 294.
- 1 is a factor of every number. Eg. 1 is a factor of 1050 and also of 294.
- Every number is a factor of zero (0), since 1050 x 0 = 0 and 294 x 0 = 0.
Steps to find Factors of 1050 and 294
- Step 1. Find all the numbers that would divide 1050 and 294 without leaving any remainder. Starting with the number 1 upto 525 (half of 1050) and 1 upto 147 (half of 294). The number 1 and the number itself are always factors of the given number.
1050 ÷ 1 : Remainder = 0
294 ÷ 1 : Remainder = 0
1050 ÷ 2 : Remainder = 0
294 ÷ 2 : Remainder = 0
1050 ÷ 3 : Remainder = 0
294 ÷ 3 : Remainder = 0
1050 ÷ 5 : Remainder = 0
294 ÷ 6 : Remainder = 0
1050 ÷ 6 : Remainder = 0
294 ÷ 7 : Remainder = 0
1050 ÷ 7 : Remainder = 0
294 ÷ 14 : Remainder = 0
1050 ÷ 10 : Remainder = 0
294 ÷ 21 : Remainder = 0
1050 ÷ 14 : Remainder = 0
294 ÷ 42 : Remainder = 0
1050 ÷ 15 : Remainder = 0
294 ÷ 49 : Remainder = 0
1050 ÷ 21 : Remainder = 0
294 ÷ 98 : Remainder = 0
1050 ÷ 25 : Remainder = 0
294 ÷ 147 : Remainder = 0
1050 ÷ 30 : Remainder = 0
294 ÷ 294 : Remainder = 0
1050 ÷ 35 : Remainder = 0
1050 ÷ 42 : Remainder = 0
1050 ÷ 50 : Remainder = 0
1050 ÷ 70 : Remainder = 0
1050 ÷ 75 : Remainder = 0
1050 ÷ 105 : Remainder = 0
1050 ÷ 150 : Remainder = 0
1050 ÷ 175 : Remainder = 0
1050 ÷ 210 : Remainder = 0
1050 ÷ 350 : Remainder = 0
1050 ÷ 525 : Remainder = 0
1050 ÷ 1050 : Remainder = 0
Hence, Factors of
1050 are 1, 2, 3, 5, 6, 7, 10, 14, 15, 21, 25, 30, 35, 42, 50, 70, 75, 105, 150, 175, 210, 350, 525, and 1050
And, Factors of
294 are 1, 2, 3, 6, 7, 14, 21, 42, 49, 98, 147, and 294
Examples of GCF
What is the relation between LCM and GCF (Greatest Common Factor)?GCF and LCM of two numbers can be related as GCF(1050, 294) = ( 1050 * 294 ) / LCM(1050, 294) = 42.
What is the GCF of 1050 and 294?GCF of 1050 and 294 is 42.
Ram has 1050 cans of Pepsi and 294 cans of Coca Cola. He wants to create identical refreshment tables that will be organized in his house warming party. He also doesn't want to have any can left over. What is the greatest number of tables that Ram can arrange?To find the greatest number of tables that Ram can stock we need to find the GCF of 1050 and 294. Hence GCF of 1050 and 294 is 42. So the number of tables that can be arranged is 42.
Rubel is creating individual servings of starters for her birthday party. He has 1050 pizzas and 294 hamburgers. He wants each serving to be identical, with no left overs. Can you help Rubel in arranging the same in greatest possible way?The greatest number of servings Rubel can create would be equal to the GCF of 1050 and 294. Thus GCF of 1050 and 294 is 42.
Ariel is making ready to eat meals to share with friends. She has 1050 bottles of water and 294 cans of food, which she would like to distribute equally, with no left overs. What is the greatest number of boxes Ariel can make?The greatest number of boxes Ariel can make would be equal to GCF of 1050 and 294. So the GCF of 1050 and 294 is 42.
Mary has 1050 blue buttons and 294 white buttons. She wants to place them in identical groups without any buttons left, in the greatest way possible. Can you help Mary arranging them in groups?Greatest possible way in which Mary can arrange them in groups would be GCF of 1050 and 294. Hence, the GCF of 1050 and 294 or the greatest arrangement is 42.
Kamal is making identical balloon arrangements for a party. He has 1050 maroon balloons, and 294 orange balloons. He wants each arrangement tohave the same number of each color. What is the greatest number of arrangements that he can make if every balloon is used?The greatest number of arrangements that he can make if every balloon is used would be equal to GCF of 1050 and 294. So the GCF of 1050 and 294 is 42.
Kunal is making baskets full of nuts and dried fruits. He has 1050 bags of nuts and 294 bags of dried fruits. He wants each basket to be identical, containing the same combination of bags of nuts and bags of driesn fruits, with no left overs. What is the greatest number of baskets that Kunal can make?the greatest number of baskets that Kunal can make would be equal to GCF of 1050 and 294. So the GCF of 1050 and 294 is 42.
To energize public transportation, Abir needs to give a few companions envelopes with transport tickets, and metro tickets in them. On the off chance that he has 1050 bus tickets and 294 metro tickets to be parted similarly among the envelopes, and he need no tickets left. What is the greatest number of envelopes Abir can make?To make the greatest number of envelopes Abir needs to find out the GCF of 1050 and 294. Hence, GCF of 1050 and 294 is 42.