What is GCF of 1650 and 1223?


Steps to find GCF of 1650 and 1223

Example: Find gcf of 1650 and 1223

  • Factors for 1650: 1, 2, 3, 5, 6, 10, 11, 15, 22, 25, 30, 33, 50, 55, 66, 75, 110, 150, 165, 275, 330, 550, 825, 1650
  • Factors for 1223: 1, 1223

Hence, GCf of 1650 and 1223 is 1

Definition of GCF

Greatest common factor commonly known as GCF of the two numbers is the highest possible number which completely divides given numbers, i.e. without leaving any remainder. It is represented as GCF (1650, 1223).

Properties of GCF

  • Given two numbers 1650 and 1223, such that GCF is 1 where 1 will always be less than 1650 and 1223.
  • GCF of two numbers is always equal to 1 in case given numbers are consecutive.
  • The product of GCF and LCM of two given numbers is equal to the product of two numbers.
  • The GCF of two given numbers is either 1 or the number itself if one of them is a prime number.

What are factors?

In mathematics, a factor is that number which divides into another number exactly, without leaving a remainder. A factor of a number can be positive or negative.

Properties of Factors

  • Each number is a factor of itself. Eg. 1650 and 1223 are factors of themselves respectively.
  • Every number other than 1 has at least two factors, namely the number itself and 1.
  • Every factor of a number is an exact divisor of that number, example 1, 2, 3, 5, 6, 10, 11, 15, 22, 25, 30, 33, 50, 55, 66, 75, 110, 150, 165, 275, 330, 550, 825, 1650 are exact divisors of 1650 and 1, 1223 are exact divisors of 1223.
  • 1 is a factor of every number. Eg. 1 is a factor of 1650 and also of 1223.
  • Every number is a factor of zero (0), since 1650 x 0 = 0 and 1223 x 0 = 0.

Steps to find Factors of 1650 and 1223

  • Step 1. Find all the numbers that would divide 1650 and 1223 without leaving any remainder. Starting with the number 1 upto 825 (half of 1650) and 1 upto 611 (half of 1223). The number 1 and the number itself are always factors of the given number.
    1650 ÷ 1 : Remainder = 0
    1223 ÷ 1 : Remainder = 0
    1650 ÷ 2 : Remainder = 0
    1223 ÷ 1223 : Remainder = 0
    1650 ÷ 3 : Remainder = 0
    1650 ÷ 5 : Remainder = 0
    1650 ÷ 6 : Remainder = 0
    1650 ÷ 10 : Remainder = 0
    1650 ÷ 11 : Remainder = 0
    1650 ÷ 15 : Remainder = 0
    1650 ÷ 22 : Remainder = 0
    1650 ÷ 25 : Remainder = 0
    1650 ÷ 30 : Remainder = 0
    1650 ÷ 33 : Remainder = 0
    1650 ÷ 50 : Remainder = 0
    1650 ÷ 55 : Remainder = 0
    1650 ÷ 66 : Remainder = 0
    1650 ÷ 75 : Remainder = 0
    1650 ÷ 110 : Remainder = 0
    1650 ÷ 150 : Remainder = 0
    1650 ÷ 165 : Remainder = 0
    1650 ÷ 275 : Remainder = 0
    1650 ÷ 330 : Remainder = 0
    1650 ÷ 550 : Remainder = 0
    1650 ÷ 825 : Remainder = 0
    1650 ÷ 1650 : Remainder = 0

Hence, Factors of 1650 are 1, 2, 3, 5, 6, 10, 11, 15, 22, 25, 30, 33, 50, 55, 66, 75, 110, 150, 165, 275, 330, 550, 825, and 1650

And, Factors of 1223 are 1 and 1223

Examples of GCF

Sammy baked 1650 chocolate cookies and 1223 fruit and nut cookies to package in plastic containers for her friends at college. She wants to divide the cookies into identical boxes so that each box has the same number of each kind of cookies. She wishes that each box should have greatest number of cookies possible, how many plastic boxes does she need?

Since Sammy wants to pack greatest number of cookies possible. So for calculating total number of boxes required we need to calculate the GCF of 1650 and 1223.
GCF of 1650 and 1223 is 1.

A class has 1650 boys and 1223 girls. A choir teacher wants to form a choir team from this class such that the students are standing in equal rows also girls or boys will be in each row. Teacher wants to know the greatest number of students that could be in each row, can you help him?

To find the greatest number of students that could be in each row, we need to find the GCF of 1650 and 1223. Hence, GCF of 1650 and 1223 is 1.

What is the difference between GCF and LCM?

Major and simple difference betwen GCF and LCM is that GCF gives you the greatest common factor while LCM finds out the least common factor possible for the given numbers.

Ram has 1650 cans of Pepsi and 1223 cans of Coca Cola. He wants to create identical refreshment tables that will be organized in his house warming party. He also doesn't want to have any can left over. What is the greatest number of tables that Ram can arrange?

To find the greatest number of tables that Ram can stock we need to find the GCF of 1650 and 1223. Hence GCF of 1650 and 1223 is 1. So the number of tables that can be arranged is 1.

Ariel is making ready to eat meals to share with friends. She has 1650 bottles of water and 1223 cans of food, which she would like to distribute equally, with no left overs. What is the greatest number of boxes Ariel can make?

The greatest number of boxes Ariel can make would be equal to GCF of 1650 and 1223. So the GCF of 1650 and 1223 is 1.

Mary has 1650 blue buttons and 1223 white buttons. She wants to place them in identical groups without any buttons left, in the greatest way possible. Can you help Mary arranging them in groups?

Greatest possible way in which Mary can arrange them in groups would be GCF of 1650 and 1223. Hence, the GCF of 1650 and 1223 or the greatest arrangement is 1.

Kamal is making identical balloon arrangements for a party. He has 1650 maroon balloons, and 1223 orange balloons. He wants each arrangement tohave the same number of each color. What is the greatest number of arrangements that he can make if every balloon is used?

The greatest number of arrangements that he can make if every balloon is used would be equal to GCF of 1650 and 1223. So the GCF of 1650 and 1223 is 1.

Kunal is making baskets full of nuts and dried fruits. He has 1650 bags of nuts and 1223 bags of dried fruits. He wants each basket to be identical, containing the same combination of bags of nuts and bags of driesn fruits, with no left overs. What is the greatest number of baskets that Kunal can make?

the greatest number of baskets that Kunal can make would be equal to GCF of 1650 and 1223. So the GCF of 1650 and 1223 is 1.

To energize public transportation, Abir needs to give a few companions envelopes with transport tickets, and metro tickets in them. On the off chance that he has 1650 bus tickets and 1223 metro tickets to be parted similarly among the envelopes, and he need no tickets left. What is the greatest number of envelopes Abir can make?

To make the greatest number of envelopes Abir needs to find out the GCF of 1650 and 1223. Hence, GCF of 1650 and 1223 is 1.