GCF of 24 and 66 is 6

- Find all the numbers that would divide 24 and 66 without leaving any remainder as explained in factors below.
- Find the greatest common factor from the list of factors for 24 and 66, and read off the answer!

- Factors for
**24: 1, 2, 3, 4, 6, 8, 12, 24** - Factors for
**66: 1, 2, 3, 6, 11, 22, 33, 66**

Hence, GCf of
*24*
and
*66*
is **6**

GCF or greatest common factor of two or more numbers is defined as largest possible number or integer which is the factor of all given number or in other words we can say that largest possible common number which completely divides the given numbers. GCF of two numbers can be represented as GCF (24, 66).

- The GCF of two or more given numbers cannot be greater than any of the given number. Eg- GCF of 24 and 66 is 6, where 6 is less than both 24 and 66.
- GCF of two consecutive numbers is always 1.
- The product of GCF and LCM of two given numbers is equal to the product of two numbers.
- The GCF of two given numbers where one of them is a prime number is either 1 or the number itself.

In mathematics, a factor is a number which divides into another number exactly, without leaving any remainder. A factor of a number can be positive of negative.

- Each number is a factor of itself. Eg. 24 and 66 are factors of themselves respectively.
- 1 is a factor of every number. Eg. 1 is a factor of 24 and also of 66.
- Every number is a factor of zero (0), since 24 x 0 = 0 and 66 x 0 = 0.
- Every number other than 1 has at least two factors, namely the number itself and 1.
- Every factor of a number is an exact divisor of that number, example 1, 2, 3, 4, 6, 8, 12, 24 are exact divisors of 24 and 1, 2, 3, 6, 11, 22, 33, 66 are exact divisors of 66.
- Factors of 24 are 1, 2, 3, 4, 6, 8, 12, 24. Each factor divides 24 without leaving a remainder.

Simlarly, factors of 66 are 1, 2, 3, 6, 11, 22, 33, 66. Each factor divides 66 without leaving a remainder. - Every factor of a number is less than or equal to the number, eg. 1, 2, 3, 4, 6, 8, 12, 24 are all less than or equal to 24 and 1, 2, 3, 6, 11, 22, 33, 66 are all less than or equal to 66.

**Step 1.**Find all the numbers that would divide 24 and 66 without leaving any remainder. Starting with the number 1 upto 12 (half of 24) and 1 upto 33 (half of 66). The number 1 and the number itself are always factors of the given number.24 ÷ 1 : Remainder = 066 ÷ 1 : Remainder = 024 ÷ 2 : Remainder = 066 ÷ 2 : Remainder = 024 ÷ 3 : Remainder = 066 ÷ 3 : Remainder = 024 ÷ 4 : Remainder = 066 ÷ 6 : Remainder = 024 ÷ 6 : Remainder = 066 ÷ 11 : Remainder = 024 ÷ 8 : Remainder = 066 ÷ 22 : Remainder = 024 ÷ 12 : Remainder = 066 ÷ 33 : Remainder = 024 ÷ 24 : Remainder = 066 ÷ 66 : Remainder = 0

Hence, Factors of
*24* are **1, 2, 3, 4, 6, 8, 12, and 24**

And, Factors of
*66* are **1, 2, 3, 6, 11, 22, 33, and 66**

GCF and LCM of two numbers can be related as GCF(24, 66) = ( 24 * 66 ) / LCM(24, 66) = 6.

GCF of 24 and 66 is 6.

To find the greatest number of tables that Ram can stock we need to find the GCF of 24 and 66. Hence GCF of 24 and 66 is 6. So the number of tables that can be arranged is 6.

The greatest number of servings Rubel can create would be equal to the GCF of 24 and 66. Thus GCF of 24 and 66 is 6.

The greatest number of boxes Ariel can make would be equal to GCF of 24 and 66. So the GCF of 24 and 66 is 6.

Greatest possible way in which Mary can arrange them in groups would be GCF of 24 and 66. Hence, the GCF of 24 and 66 or the greatest arrangement is 6.

The greatest number of arrangements that he can make if every balloon is used would be equal to GCF of 24 and 66. So the GCF of 24 and 66 is 6.

the greatest number of baskets that Kunal can make would be equal to GCF of 24 and 66. So the GCF of 24 and 66 is 6.

To make the greatest number of envelopes Abir needs to find out the GCF of 24 and 66. Hence, GCF of 24 and 66 is 6.