What is GCF of 248 and 558?


Steps to find GCF of 248 and 558

Example: Find gcf of 248 and 558

  • Factors for 248: 1, 2, 4, 8, 31, 62, 124, 248
  • Factors for 558: 1, 2, 3, 6, 9, 18, 31, 62, 93, 186, 279, 558

Hence, GCf of 248 and 558 is 62

What does GCF mean in mathematics?

Greatest Common Fcator (GCF) or also sometimes written as greates common divisor is the largest number that can evenly divide the given two numbers. GCF is represented as GCF (248, 558).

Properties of GCF

  • The GCF of two or more given numbers cannot be greater than any of the given number. Eg- GCF of 248 and 558 is 62, where 62 is less than both 248 and 558.
  • GCF of two consecutive numbers is always 1.
  • The product of GCF and LCM of two given numbers is equal to the product of two numbers.
  • The GCF of two given numbers where one of them is a prime number is either 1 or the number itself.

What is the definition of factors?

In mathematics, factors are number, algebraic expressions which when multiplied together produce desired product. A factor of a number can be positive or negative.

Properties of Factors

  • Each number is a factor of itself. Eg. 248 and 558 are factors of themselves respectively.
  • 1 is a factor of every number. Eg. 1 is a factor of 248 and also of 558.
  • Every number is a factor of zero (0), since 248 x 0 = 0 and 558 x 0 = 0.
  • Every number other than 1 has at least two factors, namely the number itself and 1.
  • Every factor of a number is an exact divisor of that number, example 1, 2, 4, 8, 31, 62, 124, 248 are exact divisors of 248 and 1, 2, 3, 6, 9, 18, 31, 62, 93, 186, 279, 558 are exact divisors of 558.
  • Factors of 248 are 1, 2, 4, 8, 31, 62, 124, 248. Each factor divides 248 without leaving a remainder.
    Simlarly, factors of 558 are 1, 2, 3, 6, 9, 18, 31, 62, 93, 186, 279, 558. Each factor divides 558 without leaving a remainder.
  • Every factor of a number is less than or equal to the number, eg. 1, 2, 4, 8, 31, 62, 124, 248 are all less than or equal to 248 and 1, 2, 3, 6, 9, 18, 31, 62, 93, 186, 279, 558 are all less than or equal to 558.

Steps to find Factors of 248 and 558

  • Step 1. Find all the numbers that would divide 248 and 558 without leaving any remainder. Starting with the number 1 upto 124 (half of 248) and 1 upto 279 (half of 558). The number 1 and the number itself are always factors of the given number.
    248 ÷ 1 : Remainder = 0
    558 ÷ 1 : Remainder = 0
    248 ÷ 2 : Remainder = 0
    558 ÷ 2 : Remainder = 0
    248 ÷ 4 : Remainder = 0
    558 ÷ 3 : Remainder = 0
    248 ÷ 8 : Remainder = 0
    558 ÷ 6 : Remainder = 0
    248 ÷ 31 : Remainder = 0
    558 ÷ 9 : Remainder = 0
    248 ÷ 62 : Remainder = 0
    558 ÷ 18 : Remainder = 0
    248 ÷ 124 : Remainder = 0
    558 ÷ 31 : Remainder = 0
    248 ÷ 248 : Remainder = 0
    558 ÷ 62 : Remainder = 0
    558 ÷ 93 : Remainder = 0
    558 ÷ 186 : Remainder = 0
    558 ÷ 279 : Remainder = 0
    558 ÷ 558 : Remainder = 0

Hence, Factors of 248 are 1, 2, 4, 8, 31, 62, 124, and 248

And, Factors of 558 are 1, 2, 3, 6, 9, 18, 31, 62, 93, 186, 279, and 558

Examples of GCF

Sammy baked 248 chocolate cookies and 558 fruit and nut cookies to package in plastic containers for her friends at college. She wants to divide the cookies into identical boxes so that each box has the same number of each kind of cookies. She wishes that each box should have greatest number of cookies possible, how many plastic boxes does she need?

Since Sammy wants to pack greatest number of cookies possible. So for calculating total number of boxes required we need to calculate the GCF of 248 and 558.
GCF of 248 and 558 is 62.

A class has 248 boys and 558 girls. A choir teacher wants to form a choir team from this class such that the students are standing in equal rows also girls or boys will be in each row. Teacher wants to know the greatest number of students that could be in each row, can you help him?

To find the greatest number of students that could be in each row, we need to find the GCF of 248 and 558. Hence, GCF of 248 and 558 is 62.

What is the relation between LCM and GCF (Greatest Common Factor)?

GCF and LCM of two numbers can be related as GCF(248, 558) = ( 248 * 558 ) / LCM(248, 558) = 62.

What is the GCF of 248 and 558?

GCF of 248 and 558 is 62.

Ram has 248 cans of Pepsi and 558 cans of Coca Cola. He wants to create identical refreshment tables that will be organized in his house warming party. He also doesn't want to have any can left over. What is the greatest number of tables that Ram can arrange?

To find the greatest number of tables that Ram can stock we need to find the GCF of 248 and 558. Hence GCF of 248 and 558 is 62. So the number of tables that can be arranged is 62.

Rubel is creating individual servings of starters for her birthday party. He has 248 pizzas and 558 hamburgers. He wants each serving to be identical, with no left overs. Can you help Rubel in arranging the same in greatest possible way?

The greatest number of servings Rubel can create would be equal to the GCF of 248 and 558. Thus GCF of 248 and 558 is 62.

Ariel is making ready to eat meals to share with friends. She has 248 bottles of water and 558 cans of food, which she would like to distribute equally, with no left overs. What is the greatest number of boxes Ariel can make?

The greatest number of boxes Ariel can make would be equal to GCF of 248 and 558. So the GCF of 248 and 558 is 62.

Kamal is making identical balloon arrangements for a party. He has 248 maroon balloons, and 558 orange balloons. He wants each arrangement tohave the same number of each color. What is the greatest number of arrangements that he can make if every balloon is used?

The greatest number of arrangements that he can make if every balloon is used would be equal to GCF of 248 and 558. So the GCF of 248 and 558 is 62.

To energize public transportation, Abir needs to give a few companions envelopes with transport tickets, and metro tickets in them. On the off chance that he has 248 bus tickets and 558 metro tickets to be parted similarly among the envelopes, and he need no tickets left. What is the greatest number of envelopes Abir can make?

To make the greatest number of envelopes Abir needs to find out the GCF of 248 and 558. Hence, GCF of 248 and 558 is 62.