What is GCF of 2490 and 3150?


Steps to find GCF of 2490 and 3150

Example: Find gcf of 2490 and 3150

  • Factors for 2490: 1, 2, 3, 5, 6, 10, 15, 30, 83, 166, 249, 415, 498, 830, 1245, 2490
  • Factors for 3150: 1, 2, 3, 5, 6, 7, 9, 10, 14, 15, 18, 21, 25, 30, 35, 42, 45, 50, 63, 70, 75, 90, 105, 126, 150, 175, 210, 225, 315, 350, 450, 525, 630, 1050, 1575, 3150

Hence, GCf of 2490 and 3150 is 30

Definition of GCF

Greatest common factor commonly known as GCF of the two numbers is the highest possible number which completely divides given numbers, i.e. without leaving any remainder. It is represented as GCF (2490, 3150).

Properties of GCF

  • Given two numbers 2490 and 3150, such that GCF is 30 where 30 will always be less than 2490 and 3150.
  • GCF of two numbers is always equal to 1 in case given numbers are consecutive.
  • The product of GCF and LCM of two given numbers is equal to the product of two numbers.
  • The GCF of two given numbers is either 1 or the number itself if one of them is a prime number.

What are factors?

In mathematics, a factor is that number which divides into another number exactly, without leaving a remainder. A factor of a number can be positive or negative.

Properties of Factors

  • Each number is a factor of itself. Eg. 2490 and 3150 are factors of themselves respectively.
  • Every number other than 1 has at least two factors, namely the number itself and 1.
  • Every factor of a number is an exact divisor of that number, example 1, 2, 3, 5, 6, 10, 15, 30, 83, 166, 249, 415, 498, 830, 1245, 2490 are exact divisors of 2490 and 1, 2, 3, 5, 6, 7, 9, 10, 14, 15, 18, 21, 25, 30, 35, 42, 45, 50, 63, 70, 75, 90, 105, 126, 150, 175, 210, 225, 315, 350, 450, 525, 630, 1050, 1575, 3150 are exact divisors of 3150.
  • 1 is a factor of every number. Eg. 1 is a factor of 2490 and also of 3150.
  • Every number is a factor of zero (0), since 2490 x 0 = 0 and 3150 x 0 = 0.

Steps to find Factors of 2490 and 3150

  • Step 1. Find all the numbers that would divide 2490 and 3150 without leaving any remainder. Starting with the number 1 upto 1245 (half of 2490) and 1 upto 1575 (half of 3150). The number 1 and the number itself are always factors of the given number.
    2490 ÷ 1 : Remainder = 0
    3150 ÷ 1 : Remainder = 0
    2490 ÷ 2 : Remainder = 0
    3150 ÷ 2 : Remainder = 0
    2490 ÷ 3 : Remainder = 0
    3150 ÷ 3 : Remainder = 0
    2490 ÷ 5 : Remainder = 0
    3150 ÷ 5 : Remainder = 0
    2490 ÷ 6 : Remainder = 0
    3150 ÷ 6 : Remainder = 0
    2490 ÷ 10 : Remainder = 0
    3150 ÷ 7 : Remainder = 0
    2490 ÷ 15 : Remainder = 0
    3150 ÷ 9 : Remainder = 0
    2490 ÷ 30 : Remainder = 0
    3150 ÷ 10 : Remainder = 0
    2490 ÷ 83 : Remainder = 0
    3150 ÷ 14 : Remainder = 0
    2490 ÷ 166 : Remainder = 0
    3150 ÷ 15 : Remainder = 0
    2490 ÷ 249 : Remainder = 0
    3150 ÷ 18 : Remainder = 0
    2490 ÷ 415 : Remainder = 0
    3150 ÷ 21 : Remainder = 0
    2490 ÷ 498 : Remainder = 0
    3150 ÷ 25 : Remainder = 0
    2490 ÷ 830 : Remainder = 0
    3150 ÷ 30 : Remainder = 0
    2490 ÷ 1245 : Remainder = 0
    3150 ÷ 35 : Remainder = 0
    2490 ÷ 2490 : Remainder = 0
    3150 ÷ 42 : Remainder = 0
    3150 ÷ 45 : Remainder = 0
    3150 ÷ 50 : Remainder = 0
    3150 ÷ 63 : Remainder = 0
    3150 ÷ 70 : Remainder = 0
    3150 ÷ 75 : Remainder = 0
    3150 ÷ 90 : Remainder = 0
    3150 ÷ 105 : Remainder = 0
    3150 ÷ 126 : Remainder = 0
    3150 ÷ 150 : Remainder = 0
    3150 ÷ 175 : Remainder = 0
    3150 ÷ 210 : Remainder = 0
    3150 ÷ 225 : Remainder = 0
    3150 ÷ 315 : Remainder = 0
    3150 ÷ 350 : Remainder = 0
    3150 ÷ 450 : Remainder = 0
    3150 ÷ 525 : Remainder = 0
    3150 ÷ 630 : Remainder = 0
    3150 ÷ 1050 : Remainder = 0
    3150 ÷ 1575 : Remainder = 0
    3150 ÷ 3150 : Remainder = 0

Hence, Factors of 2490 are 1, 2, 3, 5, 6, 10, 15, 30, 83, 166, 249, 415, 498, 830, 1245, and 2490

And, Factors of 3150 are 1, 2, 3, 5, 6, 7, 9, 10, 14, 15, 18, 21, 25, 30, 35, 42, 45, 50, 63, 70, 75, 90, 105, 126, 150, 175, 210, 225, 315, 350, 450, 525, 630, 1050, 1575, and 3150

Examples of GCF

What is the relation between LCM and GCF (Greatest Common Factor)?

GCF and LCM of two numbers can be related as GCF(2490, 3150) = ( 2490 * 3150 ) / LCM(2490, 3150) = 30.

What is the GCF of 2490 and 3150?

GCF of 2490 and 3150 is 30.

Ram has 2490 cans of Pepsi and 3150 cans of Coca Cola. He wants to create identical refreshment tables that will be organized in his house warming party. He also doesn't want to have any can left over. What is the greatest number of tables that Ram can arrange?

To find the greatest number of tables that Ram can stock we need to find the GCF of 2490 and 3150. Hence GCF of 2490 and 3150 is 30. So the number of tables that can be arranged is 30.

Rubel is creating individual servings of starters for her birthday party. He has 2490 pizzas and 3150 hamburgers. He wants each serving to be identical, with no left overs. Can you help Rubel in arranging the same in greatest possible way?

The greatest number of servings Rubel can create would be equal to the GCF of 2490 and 3150. Thus GCF of 2490 and 3150 is 30.

Ariel is making ready to eat meals to share with friends. She has 2490 bottles of water and 3150 cans of food, which she would like to distribute equally, with no left overs. What is the greatest number of boxes Ariel can make?

The greatest number of boxes Ariel can make would be equal to GCF of 2490 and 3150. So the GCF of 2490 and 3150 is 30.

Mary has 2490 blue buttons and 3150 white buttons. She wants to place them in identical groups without any buttons left, in the greatest way possible. Can you help Mary arranging them in groups?

Greatest possible way in which Mary can arrange them in groups would be GCF of 2490 and 3150. Hence, the GCF of 2490 and 3150 or the greatest arrangement is 30.

Kamal is making identical balloon arrangements for a party. He has 2490 maroon balloons, and 3150 orange balloons. He wants each arrangement tohave the same number of each color. What is the greatest number of arrangements that he can make if every balloon is used?

The greatest number of arrangements that he can make if every balloon is used would be equal to GCF of 2490 and 3150. So the GCF of 2490 and 3150 is 30.

Kunal is making baskets full of nuts and dried fruits. He has 2490 bags of nuts and 3150 bags of dried fruits. He wants each basket to be identical, containing the same combination of bags of nuts and bags of driesn fruits, with no left overs. What is the greatest number of baskets that Kunal can make?

the greatest number of baskets that Kunal can make would be equal to GCF of 2490 and 3150. So the GCF of 2490 and 3150 is 30.

To energize public transportation, Abir needs to give a few companions envelopes with transport tickets, and metro tickets in them. On the off chance that he has 2490 bus tickets and 3150 metro tickets to be parted similarly among the envelopes, and he need no tickets left. What is the greatest number of envelopes Abir can make?

To make the greatest number of envelopes Abir needs to find out the GCF of 2490 and 3150. Hence, GCF of 2490 and 3150 is 30.