What is GCF of 33 and 228?


Steps to find GCF of 33 and 228

Example: Find gcf of 33 and 228

  • Factors for 33: 1, 3, 11, 33
  • Factors for 228: 1, 2, 3, 4, 6, 12, 19, 38, 57, 76, 114, 228

Hence, GCf of 33 and 228 is 3

What does GCF mean in mathematics?

Greatest Common Fcator (GCF) or also sometimes written as greates common divisor is the largest number that can evenly divide the given two numbers. GCF is represented as GCF (33, 228).

Properties of GCF

  • The GCF of two or more given numbers is always less than the given numbers. Eg- GCF of 33 and 228 is 3, where 3 is less than both the numbers.
  • If the given numbers are consecutive than GCF is always 1.
  • Product of two numbers is always equal to the product of their GCF and LCM.
  • The GCF of two given numbers where one of them is a prime number is either 1 or the number itself.

What is the definition of factors?

In mathematics, factors are number, algebraic expressions which when multiplied together produce desired product. A factor of a number can be positive or negative.

Properties of Factors

  • Every factor of a number is an exact divisor of that number, example 1, 3, 11, 33 are exact divisors of 33 and 1, 2, 3, 4, 6, 12, 19, 38, 57, 76, 114, 228 are exact divisors of 228.
  • Every number other than 1 has at least two factors, namely the number itself and 1.
  • Each number is a factor of itself. Eg. 33 and 228 are factors of themselves respectively.
  • 1 is a factor of every number. Eg. 1 is a factor of 33 and also of 228.

Steps to find Factors of 33 and 228

  • Step 1. Find all the numbers that would divide 33 and 228 without leaving any remainder. Starting with the number 1 upto 16 (half of 33) and 1 upto 114 (half of 228). The number 1 and the number itself are always factors of the given number.
    33 ÷ 1 : Remainder = 0
    228 ÷ 1 : Remainder = 0
    33 ÷ 3 : Remainder = 0
    228 ÷ 2 : Remainder = 0
    33 ÷ 11 : Remainder = 0
    228 ÷ 3 : Remainder = 0
    33 ÷ 33 : Remainder = 0
    228 ÷ 4 : Remainder = 0
    228 ÷ 6 : Remainder = 0
    228 ÷ 12 : Remainder = 0
    228 ÷ 19 : Remainder = 0
    228 ÷ 38 : Remainder = 0
    228 ÷ 57 : Remainder = 0
    228 ÷ 76 : Remainder = 0
    228 ÷ 114 : Remainder = 0
    228 ÷ 228 : Remainder = 0

Hence, Factors of 33 are 1, 3, 11, and 33

And, Factors of 228 are 1, 2, 3, 4, 6, 12, 19, 38, 57, 76, 114, and 228

Examples of GCF

What is the relation between LCM and GCF (Greatest Common Factor)?

GCF and LCM of two numbers can be related as GCF(33, 228) = ( 33 * 228 ) / LCM(33, 228) = 3.

What is the GCF of 33 and 228?

GCF of 33 and 228 is 3.

Ram has 33 cans of Pepsi and 228 cans of Coca Cola. He wants to create identical refreshment tables that will be organized in his house warming party. He also doesn't want to have any can left over. What is the greatest number of tables that Ram can arrange?

To find the greatest number of tables that Ram can stock we need to find the GCF of 33 and 228. Hence GCF of 33 and 228 is 3. So the number of tables that can be arranged is 3.

Rubel is creating individual servings of starters for her birthday party. He has 33 pizzas and 228 hamburgers. He wants each serving to be identical, with no left overs. Can you help Rubel in arranging the same in greatest possible way?

The greatest number of servings Rubel can create would be equal to the GCF of 33 and 228. Thus GCF of 33 and 228 is 3.

Ariel is making ready to eat meals to share with friends. She has 33 bottles of water and 228 cans of food, which she would like to distribute equally, with no left overs. What is the greatest number of boxes Ariel can make?

The greatest number of boxes Ariel can make would be equal to GCF of 33 and 228. So the GCF of 33 and 228 is 3.

Mary has 33 blue buttons and 228 white buttons. She wants to place them in identical groups without any buttons left, in the greatest way possible. Can you help Mary arranging them in groups?

Greatest possible way in which Mary can arrange them in groups would be GCF of 33 and 228. Hence, the GCF of 33 and 228 or the greatest arrangement is 3.

Kamal is making identical balloon arrangements for a party. He has 33 maroon balloons, and 228 orange balloons. He wants each arrangement tohave the same number of each color. What is the greatest number of arrangements that he can make if every balloon is used?

The greatest number of arrangements that he can make if every balloon is used would be equal to GCF of 33 and 228. So the GCF of 33 and 228 is 3.

Kunal is making baskets full of nuts and dried fruits. He has 33 bags of nuts and 228 bags of dried fruits. He wants each basket to be identical, containing the same combination of bags of nuts and bags of driesn fruits, with no left overs. What is the greatest number of baskets that Kunal can make?

the greatest number of baskets that Kunal can make would be equal to GCF of 33 and 228. So the GCF of 33 and 228 is 3.

To energize public transportation, Abir needs to give a few companions envelopes with transport tickets, and metro tickets in them. On the off chance that he has 33 bus tickets and 228 metro tickets to be parted similarly among the envelopes, and he need no tickets left. What is the greatest number of envelopes Abir can make?

To make the greatest number of envelopes Abir needs to find out the GCF of 33 and 228. Hence, GCF of 33 and 228 is 3.