Prime Factors of 1042 are 2 and 521
To find the primefactors of 1042 using the division method, follow these steps:
So, the prime factorization of 1042 is, 1042 = 2 x 521.
We can follow the same procedure using the factor tree of 1042 as shown below:
So, the prime factorization of 1042 is, 1042 = 2 x 521.
Prime numbers, in mathematics are all those natural numbers greater than 1 that have exactly 2 factors which are 1 and the number itself. When we express any number as the product of these prime numbers than these prime numbers become prime factors of that number. Eg- Prime Factors of 1042 are 2 x 521.
false, 1042 is not a prime number.
To find prime factorization of 1042 easily you can refer to the steps given on this page step by step.
The largest prime factor of 1042 is 521.
Prime factors of 1042 are 2 x 521. Therefore, their sum is 523.
Prime factors of 1042 are 2 x 521. Therefore, their product is 1042.
Prime factors of 1042 are 2 , 521.
Prime factors of 1042 are 2 , 521, out of which 521 are odd numbers. So, the sum of odd prime factors of 1042 is 521 = 521.
Yes there is a even prime factor of 1042.
Prime factors of 1042 are 2 , 521, out of which 521 are odd numbers. So, the product of odd prime factors of 1042 is 521 = 521.