Prime Factors of 2142 are 2, 3, 3, 7, and 17
To find the primefactors of 2142 using the division method, follow these steps:
So, the prime factorization of 2142 is, 2142 = 2 x 3 x 3 x 7 x 17.
We can follow the same procedure using the factor tree of 2142 as shown below:
So, the prime factorization of 2142 is, 2142 = 2 x 3 x 3 x 7 x 17.
Prime numbers, in mathematics are all those natural numbers greater than 1 that have exactly 2 factors which are 1 and the number itself. When we express any number as the product of these prime numbers than these prime numbers become prime factors of that number. Eg- Prime Factors of 2142 are 2 x 3 x 3 x 7 x 17.
Smallest prime factor of 2142 is 2.
No 2142 is not a perfect square.
Prime factorization of 2142 is 2 x 3 x 3 x 7 x 17.
Factors of 2142 are 1 , 2 , 3 , 6 , 7 , 9 , 14 , 17 , 18 , 21 , 34 , 42 , 51 , 63 , 102 , 119 , 126 , 153 , 238 , 306 , 357 , 714 , 1071 , 2142.
Prime factors of 2142 are 2 x 3 x 3 x 7 x 17. Therefore, their product is 2142.
Prime factors of 2142 are 2 , 3 , 3 , 7 , 17.
Prime factors of 2142 are 2 , 3 , 3 , 7 , 17, out of which 3 , 3 , 7 , 17 are odd numbers. So, the sum of odd prime factors of 2142 is 3 + 3 + 7 + 17 = 30.
Yes there is a even prime factor of 2142.
Prime factors of 2142 are 2 , 3 , 3 , 7 , 17, out of which 3 , 3 , 7 , 17 are odd numbers. So, the product of odd prime factors of 2142 is 3 x 3 x 7 x 17 = 1071.