Prime Factors of 40002

Steps to find Prime Factors of 40002 by Division Method

To find the primefactors of 40002 using the division method, follow these steps:

• Step 1. Start dividing 40002 by the smallest prime number, i.e., 2, 3, 5, and so on. Find the smallest prime factor of the number.
• Step 2. After finding the smallest prime factor of the number 40002, which is 2. Divide 40002 by 2 to obtain the quotient (20001).
  40002 ÷ 2 = 20001
• Step 3. Repeat step 1 with the obtained quotient (20001).
  20001 ÷ 3 = 6667
  6667 ÷ 59 = 113
  113 ÷ 113 = 1

So, the prime factorization of 40002 is, 40002 = 2 x 3 x 59 x 113.

Steps to find Prime Factors of 40002 by Factor Tree Method

We can follow the same procedure using the factor tree of 40002 as shown below:

So, the prime factorization of 40002 is, 40002 = 2 x 3 x 59 x 113.

How do you define Prime Factors of a number?

Prime numbers, in mathematics are all those natural numbers greater than 1 that have exactly 2 factors which are 1 and the number itself. When we express any number as the product of these prime numbers than these prime numbers become prime factors of that number. Eg- Prime Factors of 40002 are 2 x 3 x 59 x 113.

Properties of Prime Factors

• Two prime factors of a given number are always coprime to each other.
• 2 is the only even prime factor any number can have.
• Two prime factors are always coprime to each other.
• 1 is neither a prime number nor a composite number and also 1 is the factor of every given number. So, 1 is the factor of 40002 but not a prime factor of 40002.

Frequently Asked Questions

• Is 40002 a prime number?

  false, 40002 is not a prime number.

• How to find prime factorization of 40002 easily?

  To find prime factorization of 40002 easily you can refer to the steps given on this page step by step.

• Which is the largest prime factors of 40002?

  The largest prime factor of 40002 is 113.

• What is the sum of all prime factors of 40002?

  Prime factors of 40002 are 2 x 3 x 59 x 113. Therefore, their sum is 177.

• What is the product of all prime factors of 40002?

  Prime factors of 40002 are 2 x 3 x 59 x 113. Therefore, their product is 40002.

• What numbers are the prime factors of 40002?

  Prime factors of 40002 are 2 , 3 , 59 , 113.

• What is the sum of all odd prime factors of 40002?

  Prime factors of 40002 are 2 , 3 , 59 , 113, out of which 3 , 59 , 113 are odd numbers. So, the sum of odd prime factors of 40002 is 3 + 59 + 113 = 175.

• Is there any even prime factor of 40002?

  Yes there is a even prime factor of 40002.

• What is the product of all odd prime factors of 40002?

  Prime factors of 40002 are 2 , 3 , 59 , 113, out of which 3 , 59 , 113 are odd numbers. So, the product of odd prime factors of 40002 is 3 x 59 x 113 = 20001.