Prime Factors of 428 are 2, 2, and 107
To find the primefactors of 428 using the division method, follow these steps:
So, the prime factorization of 428 is, 428 = 2 x 2 x 107.
We can follow the same procedure using the factor tree of 428 as shown below:
So, the prime factorization of 428 is, 428 = 2 x 2 x 107.
Prime numbers, in mathematics are all those whole numbers greater than 1 having exactly two divisors that is 1 and the number itself. When we express any number as the product of these prime numbers than these prime numbers become prime factors of that number. Eg- Prime Factors of 428 are 2 x 2 x 107.
Smallest prime factor of 428 is 2.
Prime factorization of 428 is 2 x 2 x 107.
Factors of 428 are 1 , 2 , 4 , 107 , 214 , 428.
428 is a composite number.
false, 428 is not a prime number.
The largest prime factor of 428 is 107.
Prime factors of 428 are 2 x 2 x 107. Therefore, their sum is 111.
Prime factors of 428 are 2 , 2 , 107.
Prime factors of 428 are 2 , 2 , 107, out of which 107 are odd numbers. So, the sum of odd prime factors of 428 is 107 = 107.