Prime Factors of 5002 are 2, 41, and 61
To find the primefactors of 5002 using the division method, follow these steps:
So, the prime factorization of 5002 is, 5002 = 2 x 41 x 61.
We can follow the same procedure using the factor tree of 5002 as shown below:
So, the prime factorization of 5002 is, 5002 = 2 x 41 x 61.
Prime numbers, in mathematics are all those natural numbers greater than 1 that have exactly 2 factors which are 1 and the number itself. When we express any number as the product of these prime numbers than these prime numbers become prime factors of that number. Eg- Prime Factors of 5002 are 2 x 41 x 61.
false, 5002 is not a prime number.
To find prime factorization of 5002 easily you can refer to the steps given on this page step by step.
The largest prime factor of 5002 is 61.
Prime factors of 5002 are 2 x 41 x 61. Therefore, their sum is 104.
Prime factors of 5002 are 2 x 41 x 61. Therefore, their product is 5002.
Prime factors of 5002 are 2 , 41 , 61.
Prime factors of 5002 are 2 , 41 , 61, out of which 41 , 61 are odd numbers. So, the sum of odd prime factors of 5002 is 41 + 61 = 102.
Yes there is a even prime factor of 5002.
Prime factors of 5002 are 2 , 41 , 61, out of which 41 , 61 are odd numbers. So, the product of odd prime factors of 5002 is 41 x 61 = 2501.