Prime Factors of 742 are 2, 7, and 53
To find the primefactors of 742 using the division method, follow these steps:
So, the prime factorization of 742 is, 742 = 2 x 7 x 53.
We can follow the same procedure using the factor tree of 742 as shown below:
So, the prime factorization of 742 is, 742 = 2 x 7 x 53.
Prime numbers, in mathematics are all those natural numbers greater than 1 that have exactly 2 factors which are 1 and the number itself. When we express any number as the product of these prime numbers than these prime numbers become prime factors of that number. Eg- Prime Factors of 742 are 2 x 7 x 53.
Smallest prime factor of 742 is 2.
No 742 is not a perfect square.
Prime factorization of 742 is 2 x 7 x 53.
Factors of 742 are 1 , 2 , 7 , 14 , 53 , 106 , 371 , 742.
Prime factors of 742 are 2 x 7 x 53. Therefore, their product is 742.
Prime factors of 742 are 2 , 7 , 53.
Prime factors of 742 are 2 , 7 , 53, out of which 7 , 53 are odd numbers. So, the sum of odd prime factors of 742 is 7 + 53 = 60.
Yes there is a even prime factor of 742.
Prime factors of 742 are 2 , 7 , 53, out of which 7 , 53 are odd numbers. So, the product of odd prime factors of 742 is 7 x 53 = 371.