Prime Factors of 942 are 2, 3, and 157
To find the primefactors of 942 using the division method, follow these steps:
So, the prime factorization of 942 is, 942 = 2 x 3 x 157.
We can follow the same procedure using the factor tree of 942 as shown below:
So, the prime factorization of 942 is, 942 = 2 x 3 x 157.
Prime numbers, in mathematics are all those natural numbers greater than 1 that have exactly 2 factors which are 1 and the number itself. When we express any number as the product of these prime numbers than these prime numbers become prime factors of that number. Eg- Prime Factors of 942 are 2 x 3 x 157.
Smallest prime factor of 942 is 2.
No 942 is not a perfect square.
Prime factorization of 942 is 2 x 3 x 157.
Factors of 942 are 1 , 2 , 3 , 6 , 157 , 314 , 471 , 942.
Prime factors of 942 are 2 x 3 x 157. Therefore, their product is 942.
Prime factors of 942 are 2 , 3 , 157.
Prime factors of 942 are 2 , 3 , 157, out of which 3 , 157 are odd numbers. So, the sum of odd prime factors of 942 is 3 + 157 = 160.
Yes there is a even prime factor of 942.
Prime factors of 942 are 2 , 3 , 157, out of which 3 , 157 are odd numbers. So, the product of odd prime factors of 942 is 3 x 157 = 471.