Prime Factors of 982 are 2 and 491
To find the primefactors of 982 using the division method, follow these steps:
So, the prime factorization of 982 is, 982 = 2 x 491.
We can follow the same procedure using the factor tree of 982 as shown below:
So, the prime factorization of 982 is, 982 = 2 x 491.
Prime numbers, in mathematics are all those natural numbers greater than 1 that have exactly 2 factors which are 1 and the number itself. When we express any number as the product of these prime numbers than these prime numbers become prime factors of that number. Eg- Prime Factors of 982 are 2 x 491.
Smallest prime factor of 982 is 2.
No 982 is not a perfect square.
Prime factorization of 982 is 2 x 491.
Factors of 982 are 1 , 2 , 491 , 982.
Prime factors of 982 are 2 x 491. Therefore, their product is 982.
Prime factors of 982 are 2 , 491.
Prime factors of 982 are 2 , 491, out of which 491 are odd numbers. So, the sum of odd prime factors of 982 is 491 = 491.
Yes there is a even prime factor of 982.
Prime factors of 982 are 2 , 491, out of which 491 are odd numbers. So, the product of odd prime factors of 982 is 491 = 491.