Factors of 1250 in pair are (1, 1250) , (2, 625) , (5, 250) , (10, 125) and (25, 50)

- Find all the numbers that would divide 1250 without leaving any remainder. Starting with the number 1 upto 625 (half of 1250). The number 1 and the number itself are always factors of the given number.
- Pair the factors so that their product is 1250, and read off the answer!

Factor Pair | Pair Factorization |
---|---|

1 and 1250 | 1 x 1250 = 1250 |

2 and 625 | 2 x 625 = 1250 |

5 and 250 | 5 x 250 = 1250 |

10 and 125 | 10 x 125 = 1250 |

25 and 50 | 25 x 50 = 1250 |

Since the product of two negative numbers gives a positive number, the product of the negative values of both the numbers in a pair factor will also give 1250. They are called negative pair factors.

Hence, the negative pairs of 1250 would be ( -1 , -1250 ) .

In mathematics, factor pair are often given as pair of numbers which when multiplied together give the original number. Every natural number is a product of atleast one factor pair. Eg- Factors of 1250 are 1 , 2 , 5 , 10 , 25 , 50 , 125 , 250 , 625 , 1250. So, factors of 1250 in pair are (1,1250), (2,625), (5,250), (10,125), (25,50).

In mathematics, a factor is that number which divides into another number exactly, without leaving a remainder. A factor of a number can be positive or negative.

- Each number is a factor of itself. Eg. 1250 is a factor of itself.
- Every number other than 1 has at least two factors, namely the number itself and 1.
- Every factor of a number is an exact divisor of that number, example 1, 2, 5, 10, 25, 50, 125, 250, 625, 1250 are exact divisors of 1250.
- 1 is a factor of every number. Eg. 1 is a factor of 1250.
- Every number is a factor of zero (0), since 1250 x 0 = 0.

**Step 1.**Find all the numbers that would divide 1250 without leaving any remainder. Starting with the number 1 upto 625 (half of 1250). The number 1 and the number itself are always factors of the given number.1250 ÷ 1 : Remainder = 01250 ÷ 2 : Remainder = 01250 ÷ 5 : Remainder = 01250 ÷ 10 : Remainder = 01250 ÷ 25 : Remainder = 01250 ÷ 50 : Remainder = 01250 ÷ 125 : Remainder = 01250 ÷ 250 : Remainder = 01250 ÷ 625 : Remainder = 01250 ÷ 1250 : Remainder = 0

Hence, Factors of
*1250* are **1, 2, 5, 10, 25, 50, 125, 250, 625, and 1250**

**Is 1250 a composite number?**Yes 1250 is a composite number.

**Is 1250 a prime number?**No 1250 is not a prime number.

**Is 1250 a perfect square?**No 1250 is not a perfect square.

**Write five multiples of 1250.**Five multiples of 1250 are 2500, 3750, 5000, 6250, 7500.

**Write all odd factors of 1250?**The factors of 1250 are 1, 2, 5, 10, 25, 50, 125, 250, 625, 1250.

Odd factors of 1250 are 1 , 5 , 25 , 125 , 625.

Factors of 1250 are 1, 2, 5, 10, 25, 50, 125, 250, 625, 1250. So, factors of 1250 in pair are (1,1250), (2,625), (5,250), (10,125), (25,50).

Negative factors of 1250 are -1, -2, -5, -10, -25, -50, -125, -250, -625, -1250. Hence, factors of 1250 in pair are (-1,-1250), (-2,-625), (-5,-250), (-10,-125), (-25,-50).

Factors of 1250 are 1, 2, 5, 10, 25, 50, 125, 250, 625, 1250. Positive factors of 1250 in pair are (1,1250), (2,625), (5,250), (10,125), (25,50). Negative factors of 1250 in pair are (-1,-1250), (-2,-625), (-5,-250), (-10,-125), (-25,-50).

Factors of 1250 are 1, 2, 5, 10, 25, 50, 125, 250, 625, 1250. Prime factors are 2, 5, 5, 5, 5. So, the product of all prime factors of 1250 would be 2 x 5 x 5 x 5 x 5 = 1250.

Factors of 1250 are 1, 2, 5, 10, 25, 50, 125, 250, 625, 1250.

Factors of 1250 in pair are (1,1250), (2,625), (5,250), (10,125), (25,50).

Prime factorization of 1250 is 2 x 5 x 5 x 5 x 5. Factors of 1250 in pair can be written as (1,1250), (2,625), (5,250), (10,125), (25,50).

Smallest prime factor of 1250 is 2.

Largest prime factor of 1250 is 5.