Prime Factors of 1242 are 2, 3, 3, 3, and 23
To find the primefactors of 1242 using the division method, follow these steps:
So, the prime factorization of 1242 is, 1242 = 2 x 3 x 3 x 3 x 23.
We can follow the same procedure using the factor tree of 1242 as shown below:
So, the prime factorization of 1242 is, 1242 = 2 x 3 x 3 x 3 x 23.
Prime numbers, in mathematics are all those natural numbers greater than 1 that have exactly 2 factors which are 1 and the number itself. When we express any number as the product of these prime numbers than these prime numbers become prime factors of that number. Eg- Prime Factors of 1242 are 2 x 3 x 3 x 3 x 23.
false, 1242 is not a prime number.
To find prime factorization of 1242 easily you can refer to the steps given on this page step by step.
The largest prime factor of 1242 is 23.
Prime factors of 1242 are 2 x 3 x 3 x 3 x 23. Therefore, their sum is 34.
Prime factors of 1242 are 2 x 3 x 3 x 3 x 23. Therefore, their product is 1242.
Prime factors of 1242 are 2 , 3 , 3 , 3 , 23.
Prime factors of 1242 are 2 , 3 , 3 , 3 , 23, out of which 3 , 3 , 3 , 23 are odd numbers. So, the sum of odd prime factors of 1242 is 3 + 3 + 3 + 23 = 32.
Yes there is a even prime factor of 1242.
Prime factors of 1242 are 2 , 3 , 3 , 3 , 23, out of which 3 , 3 , 3 , 23 are odd numbers. So, the product of odd prime factors of 1242 is 3 x 3 x 3 x 23 = 621.