Prime Factors of 483 are 3, 7, and 23
To find the primefactors of 483 using the division method, follow these steps:
So, the prime factorization of 483 is, 483 = 3 x 7 x 23.
We can follow the same procedure using the factor tree of 483 as shown below:
So, the prime factorization of 483 is, 483 = 3 x 7 x 23.
Prime numbers, in mathematics are all those whole numbers greater than 1 having exactly two divisors that is 1 and the number itself. When we express any number as the product of these prime numbers than these prime numbers become prime factors of that number. Eg- Prime Factors of 483 are 3 x 7 x 23.
Smallest prime factor of 483 is 3.
No 483 is not a perfect square.
Prime factorization of 483 is 3 x 7 x 23.
Prime factorization of 483 in exponential form is 3 x 7 x 23.
false, 483 is not a prime number.
The largest prime factor of 483 is 23.
Prime factors of 483 are 3 x 7 x 23. Therefore, their product is 483.
Prime factors of 483 are 3 , 7 , 23, out of which 3 , 7 , 23 are odd numbers. So, the sum of odd prime factors of 483 is 3 + 7 + 23 = 33.
Prime factors of 483 are 3 , 7 , 23, out of which 3 , 7 , 23 are odd numbers. So, the product of odd prime factors of 483 is 3 x 7 x 23 = 483.