Prime Factors of 1252 are 2, 2, and 313
To find the primefactors of 1252 using the division method, follow these steps:
So, the prime factorization of 1252 is, 1252 = 2 x 2 x 313.
We can follow the same procedure using the factor tree of 1252 as shown below:
So, the prime factorization of 1252 is, 1252 = 2 x 2 x 313.
Prime numbers, in mathematics are all those natural numbers greater than 1 that have exactly 2 factors which are 1 and the number itself. When we express any number as the product of these prime numbers than these prime numbers become prime factors of that number. Eg- Prime Factors of 1252 are 2 x 2 x 313.
Smallest prime factor of 1252 is 2.
Prime factorization of 1252 is 2 x 2 x 313.
Factors of 1252 are 1 , 2 , 4 , 313 , 626 , 1252.
1252 is a composite number.
false, 1252 is not a prime number.
The largest prime factor of 1252 is 313.
Prime factors of 1252 are 2 x 2 x 313. Therefore, their sum is 317.
Prime factors of 1252 are 2 , 2 , 313.
Prime factors of 1252 are 2 , 2 , 313, out of which 313 are odd numbers. So, the sum of odd prime factors of 1252 is 313 = 313.