Prime Factors of 2002 are 2, 7, 11, and 13
To find the primefactors of 2002 using the division method, follow these steps:
So, the prime factorization of 2002 is, 2002 = 2 x 7 x 11 x 13.
We can follow the same procedure using the factor tree of 2002 as shown below:
So, the prime factorization of 2002 is, 2002 = 2 x 7 x 11 x 13.
Prime numbers, in mathematics are all those natural numbers greater than 1 that have exactly 2 factors which are 1 and the number itself. When we express any number as the product of these prime numbers than these prime numbers become prime factors of that number. Eg- Prime Factors of 2002 are 2 x 7 x 11 x 13.
false, 2002 is not a prime number.
To find prime factorization of 2002 easily you can refer to the steps given on this page step by step.
The largest prime factor of 2002 is 13.
Prime factors of 2002 are 2 x 7 x 11 x 13. Therefore, their sum is 33.
Prime factors of 2002 are 2 x 7 x 11 x 13. Therefore, their product is 2002.
Prime factors of 2002 are 2 , 7 , 11 , 13.
Prime factors of 2002 are 2 , 7 , 11 , 13, out of which 7 , 11 , 13 are odd numbers. So, the sum of odd prime factors of 2002 is 7 + 11 + 13 = 31.
Yes there is a even prime factor of 2002.
Prime factors of 2002 are 2 , 7 , 11 , 13, out of which 7 , 11 , 13 are odd numbers. So, the product of odd prime factors of 2002 is 7 x 11 x 13 = 1001.